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`129.6 Hz``500 Hz``1000 Hz``2000 Hz`

Answer :

CSolution :

When piston moves a distance `x_(1)`, path difference changes by ` 2 x`. <br> Therefore , the path difference between maxima and consecutive minima ` = lambda//2` <br> ` 2 x = lambda//2` <br> or `lambda = 4 x = 4 xx 9 cm = 36 cm = 0.36 m` <br> `n = (v)/(lambda) = (360)/(0.36) = 1000 Hz`